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melomori [17]
4 years ago
15

Please help me with #6

Mathematics
2 answers:
Flura [38]4 years ago
8 0
I guess the answer would be either 3d+12d or 3 times d times(d+4)
hope I help.

zhenek [66]4 years ago
6 0
The answer is d+4...
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tatyana61 [14]

Answer:

P(x > 1\ and\ x < 2) = \frac{4}{25}

Step-by-step explanation:

Given

S = \{1,2,3,4,5\}

n(S) = 5

Required

P(x > 1\ and\ x < 2)

P(x > 1\ and\ x < 2) is calculated as:

P(x > 1\ and\ x < 2) = P(x > 1) * P(x < 2)

Since it is a probability with replacement, we have:

P(x > 1\ and\ x < 2) = \frac{n(x > 1)}{n(S)} * \frac{n(x < 2)}{n(S)}

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For x < 2, we have:

x < 2 = \{1\}

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P(x > 1\ and\ x < 2) = \frac{n(x > 1)}{n(S)} * \frac{n(x < 2)}{n(S)}

becomes

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