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Reil [10]
3 years ago
12

Butterfly: wingspan 20 cm silk butterfly: wingspan 4 cm​

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

(silk butterfly numerator )(butterfly denominator) 4cm/20cm = 1cm/5cm

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How do you solve <br> -178=-5x+4(-4x-13)
Effectus [21]

Answer:

x = 6

Step-by-step explanation:

  • <em><u>Pull out like factors: </u></em>

-4x - 13  =   -1 • (4x + 13)

  • <em><u>Equation at the end of step 2: </u></em>

 -178 -  (-5x +  -4 • [4x + 13] )  = 0

  • <em><u>Pull out like factors: </u></em>

  21x - 126  =   21 • (x - 6)

  • <em><u>Equation at the end of step 4: </u></em>

 21 • (x - 6)  = 0

  • <em><u>Solve:</u></em>

x-6 = 0  

  • <em><u>Add 6 to both sides of the equation:</u></em>

x = 6

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3 years ago
Greg earned $45.76 in 6.4 hours. How much did he earn per hour?
Alisiya [41]

Answer:

The answer is $7.15 (A)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Answer the problem :)
Tomtit [17]
The domain is the value of x. In this case, -3≤x≤7
the range is the value of y. in this case, -1≤y≤9

this is not a function, because the same x value has two corresponding y values. For example, when x=5, y=0 or y=8

It IS a function if every x value has only one corresponding y value. 
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3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
Which rational number is NOT greater than point A?
kramer

Step-by-step explanation:

) Every positive rational number is greater than 0. 

(ii) Every negative rational number is less than 0.

(iii) Every positive rational number is greater than every negative rational number. 

(iv) Every rational number represented by a point on the number line is greater than every rational number represented by points on its left. 

(v) Every rational number represented by a point on the number line is less than every rational number represented by paints on its right

b

5 0
3 years ago
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