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3 years ago

Help!!!!! Please!!!

Mathematics

1 answer:

miss Akunina [59]3 years ago

5 0

The equation for line E is x = 8.
This is because the line intersects the x-axis at the point (8,0)

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What is |1-8i|? A. B. C D

kondor19780726 [428]

9514 1404 393

Answer:

(b) √65

Step-by-step explanation:

The modulus of a complex number is the root of the sum of the squares of the real and imaginary parts.

|1 -8i| = √(1² +(-8)²) = √(1+64) = √65

3 0

3 years ago

These are the values in Min-Su’s data set.

Ber [7]

The answer is (4,5) (5,-5) (6,-4) (7,3) (8,1).

3 0

3 years ago

What is the check digits (d) for the master card number 5130 7201 2608 209d A)1 B)3 C)5 D)7

LenKa [72]

I hope this is just a maths problem coz if this is your card number I wouldn't be putting it on here for all to see.

6 0

3 years ago

These kittens get 1 can of cat food a day. If each can holds 6 ounces of food, how many ounces of food do they eat in one week?

Paladinen [302]

If 6=1 then 6x7= 42 so 42 oz of food per week

5 0

3 years ago

The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c

Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so $p = \frac{2}{20} = 0.1$ .

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487$

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0

3 years ago