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3 years ago

5

1 -12.166 + (-1.54)

1 answer:

castortr0y [4]3 years ago

8 0

Answer:

-12.706

Step-by-step explanation:

First we distribute: 1 - 12.166 - 1.54

Then we subtract: -12.706

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Please help. On a winter day in Alaska, the temperature at noon was -0.6°C. From noon to 3:00, the temperature increased by 1.2°

fomenos

Answer:

1st choice

Step-by-step explanation:

Temp at noon was -0.6. It increases 1.2 until 3.

-0.6+1.2

gets colder 0.4, then 0.6.

-0.6+1.2-0.4-0.6

the only correct way to put this equation as one of the other answers is by putting it as -0.6+1.2+(-0.4)+(-0.6)

hope that helped!

7 0

3 years ago

{1/8, -0.02555,0.2,-1/7} following set up numbers from least to greatest by the way there are two negatives

nata0808 [166]

Change each of the fractions into decimals.

1/8 becomes 0.125

-1/7 becomes -0.143

and -0.02555

0.2

In order from least to greatest,

-0.143, -0.02555, 0.125, 0.2

OR

-1/7, -0.02555, 1/8 and 0.2

6 0

3 years ago

The length of a rectangle is four more than its width. If the area of the rectangle is 12, find the length of the rectangle.

Kobotan [32]

Answer:

I don’t know but I have the same question with different numbers

Step-by-step explanation:

8 0

3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

-1/3x=2/5x2/3 solve this

Nat2105 [25]

I hope this helps you

8 0

3 years ago