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zhuklara [117]
4 years ago
9

When you need a fraction of a number like 1/3 of 9 how do you find out how much you need?

Mathematics
1 answer:
Natalija [7]4 years ago
5 0

To find out how much you need when you need a fraction of a number like 1/3 of 9, you can multiply the whole number by the fraction in most cases.

In some cases however, you can convert the whole number into a fraction and then divide it to get the amount in fractional units that you require.

For example:

1/3 of 9

Convert 9 to a fraction.

1/3 / 9/1

1/3 x 9/1 = 3/9

Therefore you would need 3 of 9 for 1/3.

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Please hawlp pls.......
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Answer:

(a) A(x)=160x-2x^{2}

(b) x=40\textrm{ m}

(c) Maximum area=3200 square meters

Step-by-step explanation:

(a)

Given:

Total length for fencing = 160 m

Width of the rectangle = x m.

Let the other length of the rectangle be y m.

Then, from the figure,

x+y+x=160\\2x+y=160\\y=160-2x

Now, area of a rectangle is equal to the product of its length and width.

So, area is, A(x)=xy=x(160-2x)=160x-2x^{2}

(b)

Given:

A(x)=160x-2x^{2}

For maximum area, derivative of area with respect to x must be 0.

So, \frac{dA}{dx}=0\\\frac{d}{dx}(160x-2x^{2})=0\\160-4x=0\\4x=160\\x=\frac{160}{4}=40\textrm{ m}

Therefore, for maximum area, x=40\textrm{ m}.

(c)

Given:

A(x)=160x-2x^{2}

Maximum area occurs at x=40. Plug in 40 for x in A(x) expression. This gives,

Maximum area is,

A(x=40)=160(40)-2(40)^{2}\\A(x=40)=6400-2\times 1600\\A(x=40)=6400-3200=3200\textrm{ }m^{2}

Therefore, maximum area is 3200 square meters.

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The Han dynasty lasted from 206 B.C. to 9 A.D. How many years did the dynasty last?
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Which graph represents the solution set for the inequality 1xs 18?
Vesnalui [34]

9514 1404 393

Answer:

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Step-by-step explanation:

Multiplying the inequality by 2 will eliminate the fraction and give you ...

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The "or equal to" part of the symbol means the end dot will be solid. The "less than" part of the symbol means the graph is shaded to the left of the end dot, which is at x=36. This description matches the graph shown below.

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