Answer:
1274Dac
Step-by-step explanation:
i used photomath but i think thats right hope this helps:)
Answer:
Pythagoras was the Greek geometer .
<em>Please mark me as the brainliest.</em>
Answer:
10
Step-by-step explanation:
30 - 1, 2, 3, 5, 10, 15, 30
100- 1, 2, 4, 5, 10, 20, 25
The general form of a solution of the differential equation is already provided for us:
where 
. We now want to find a solution 
such that 
and 
. Therefore, all we need to do is find the constants 
and 
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative 
first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute 
into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.
In terms of diameter (d), the area (A) of a circle is given by the formula
A = (π/4)d²
You have d=20 yd, so the area of the circle is
A = (π/4)×(20 yd)² . . . . substitute the given information into the formula
A = 100π yd² . . . . . . . . do the arithmetic
A ≈ 314.16 yd²
