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BlackZzzverrR [31]
3 years ago
13

In a shelter, the number of kennels is proportional to the number of dogs. The constant of proportionality in terms of dogs per

kennel is 3, and there are 27 dogs in the shelter. How many kennels are there?
9
15
30
81
Mathematics
2 answers:
Masja [62]3 years ago
8 0

Answer:  The correct option is (A) 9.

Step-by-step explanation:  Given that in a shelter, the number of kennels is proportional to the number of dogs. The constant of proportionality in terms of dogs per kennel is 3, and there are 27 dogs in the shelter.

We are to find the number of kennels.

Let k and d represents the number of kennels and dogs respectively in the shelter.

Then, according to the given information, we have

k\propto d\\\\\Rightarrow d\propto k\\\\\Rightarrow d=tk~~~~~~~\textup{[where t is the proportionality constant]}\\\\\Rightarrow \dfrac{d}{k}=t.

Since constant of proportionality in terms of dogs per kennel is 3, so we have

t = 3. That is,

\dfrac{d}{k}=3\\\\\\\Rightarrow k=\dfrac{d}{3}

When d = 27, then

k=\dfrac{27}{3}=9.

Thus, the number f kennels is 9.

Option (A) is CORRECT.

yaroslaw [1]3 years ago
5 0
The answer is 9 as you divide 27 by 3
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Viktor [21]

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Step-by-step explanation:

The arrow from 0 to -2 represents the initial "-2" of the problem. <em>Adding </em>-10 would put an arrow of length 10 from that point to the left to -12. However, you are <em>subtracting </em>-10, so that arrow is reversed and goes from -2 to +8.

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3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value
erik [133]

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70

\\ \tt\Rrightarrow y(2)(4)(7)=70

\\ \tt\Rrightarrow y(56)=70

\\ \tt\Rrightarrow y=\dfrac{70}{56}

\\ \tt\Rrightarrow y=\dfrac{5}{4}

#2

\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120

\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120

\\ \tt\Rrightarrow -y(2)(4)(7)=120

\\ \tt\Rrightarrow 56y=-120

\\ \tt\Rrightarrow y=\dfrac{-120}{56}

\\ \tt\Rrightarrow y=\dfrac{-15}{7}

7 0
3 years ago
Read 2 more answers
Please help!!!!due at 11 .I think the number of sodas sold was 48 but I don't know how many hotdogs were sold
Alex Ar [27]

Answer:

Number of sodas sold: 78

Number of hot dogs sold: 24

Step-by-step explanation:

Number of sodas sold = x

Number of hot dogs sold = x - 54

Total number of sodas and hot dogs = x + x - 54 = 2x - 54

Total number = 102

2x - 54 = 102

2x = 156

x = 78

Number of sodas sold = x = 78

Number of hot dogs sold = x - 54 = 78 - 54 = 24

Answer:

Number of sodas sold: 78

Number of hot dogs sold: 24

6 0
3 years ago
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