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2 years ago

F(x)=−2x+16 g(x)=4x+10 please give me the intersection points

Mathematics

2 answers:

vagabundo [1.1K]2 years ago

7 0

Answer:

(1, 14)

Step-by-step explanation:

The intersection is when both functions have same coordinates

f(x) = g(x)

Substitute to get

- 2x + 16 = 4x + 10
4x + 2x = 16 - 10
6x = 6
x = 1

The y- coordinate is

y = - 2(1) + 16 = -2 + 16 = 14

So the intersection point is (1, 14)

Maurinko [17]2 years ago

7 0

refer to this image here

hope it helps :)

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3 years ago

4. 10. 4 Test (CST):

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Based on the value of the annuity, the amount it earns, and the compounding period, the money paid to Nathan each month will be B. $5,840.62.

<h3>How much will Nathan be paid monthly?</h3>

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Find out more on the present value of an annuity at brainly.com/question/25792915.

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2 years ago

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What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

Formula for the coordinate of mid-point : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

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2 years ago

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