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3 years ago

9

You are making fruit baskets using 54 apples, 36 oranges, and 73 bananas. Explain why you cannot make identical fruit baskets wi

thout leftover fruit?

1 answer:

liq [111]3 years ago

7 0

The bananas are not an equal number so you would not have the same amount unless you take one out.

You might be interested in

Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%

beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.33$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$\sigma = 5, n = 100$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.33*\frac{5}{\sqrt{100}} = 1.165$

So the correct answer is:

1.165.

6 0

3 years ago

N squared minus eight N minus twenty equals 0

erica [24]

Answer:

n = -2 or n = 10

Step-by-step explanation:

n^2 - 8n - 20 = 0

6 0

3 years ago

Which of the following is equivalent to the expression 16x2−9?

spin [16.1K]

Answer:

(4x+3) (4x-3)

Step-by-step explanation:

5 0

2 years ago

What is the maximum value of the objective function, P, with the given constraints?

maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

$P=20x+35y$

Constraints,

$x+y \leq 12$

$5x+y \leq 20\\x \geq 0\\y \geq 0$

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

$P=20x+35y$

Point (0,0)

$P=20(0)+35(0)=0$

$P=20x+35y$

Point (0,12)

$P=20(0)+35(12)=420$

Point (2,10)

$P=20(2)+35(10)=40+350=390$

Point (4,0)

$P=20(4)+35(0)=80$

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0

3 years ago

Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0

guajiro [1.7K]

Answer:

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

$\displaystyle -3x^4+27x^2+1200=0$

If we call $y=x^2$ , our equation becomes a second-degree equation

$\displaystyle -3y^2+27y+1200=0$

Dividing by -3

$\displaystyle y^2-9y-400=0$

Factoring

$\displaystyle (y-25)(y+16)=0$

It leads to these solutions

$\displaystyle y=25\ ,\ y=-16$

Taking back the change of variable, we have for the first solution

$\displaystyle x^2=25\Rightarrow x=-5,x=5$

Now for the second solution, we get imaginary (complex) values

$\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i$

Summarizing, the four solutions for x are

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

5 0

3 years ago