What is the NEXT step in solving this system of equations, and what is the solution for the value of "y"?

Mathematics

1 answer:

Mazyrski [523]2 years ago

6 0

Answer:

There is no next step, the problem is answered!

Step-by-step explanation:

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Involves triangle centroid

Rasek [7]

Here, you do the same as the previous one, keeping in mind that X cuts TW in a 2:1 ratio.

$\bf TW-TX=XW\implies \cfrac{8a}{5}+\cfrac{1}{10}-\left(a +\cfrac{4}{5} \right)=XW
\\\\\\
\cfrac{8a}{5}+\cfrac{1}{10}-a-\cfrac{4}{5}=XW\implies \cfrac{3a}{5}-\cfrac{7}{10}=XW\\\\
-------------------------------\\\\$

$\bf TX:XW\qquad 2:1\qquad \cfrac{TX}{XW}=\cfrac{2}{1}\implies \cfrac{a+\frac{4}{5}}{\frac{3a}{5}-\frac{7}{10}}=\cfrac{2}{1}
\\\\\\
\cfrac{\frac{5a+4}{5}}{\frac{6a-7}{10}}=\cfrac{2}{1}\implies \cfrac{5a+4}{5}\cdot \cfrac{10}{6a-7}=\cfrac{2}{1}\implies \cfrac{10a+8}{6a-7}=\cfrac{2}{1}
\\\\\\
10a+8=12a-14\implies 22=2a\implies \cfrac{22}{2}=a\implies 11=a$

6 0

3 years ago

Quadrilateral ABCD is similar to quadrilateral EFGH. Find the measure of side EF

garri49 [273]

Answer:

EF = 6.6

Step-by-step explanation:

Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.

3 0

2 years ago

Five boxes of fruit snacks cost $22.50.

Viefleur [7K]

Answer:

13.5 answer is 13.5 and one cost 4.5

5 0

2 years ago

The table below represents the equation: y = 1.5x – 2 If you completed this table, would each input have exactly one output? yes

stealth61 [152]

Answer:

Step-by-step explanation: y=1.5(3)-2