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Tamiku [17]
3 years ago
5

Solve for y in terms of x.

Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

\boxed{\mathrm{Option \ 4}}

Step-by-step explanation:

Given that

y-4 = x

Adding 4 to both sides

y-4+4 = x+4\\

y = x+4

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3(-0.4n-0.7)=-3.2n-2.58
svlad2 [7]

Answer:

n=-0.24

Step-by-step explanation:

3\left(-0.4n-0.7\right)=-3.2n-2.58

Use distributive property.

-1.2n-2.1=-3.2n-2.58

-1.2n-2.1+2.1=-3.2n-2.58+2.1

-1.2n=-3.2n-0.48

-1.2n+3.2n=-3.2n-0.48+3.2n

2n=-0.48

\frac{2n}{2}=\frac{-0.48}{2}

n=-0.24

3 0
3 years ago
The diagram shows a right-angled triangle.
Margarita [4]
1/sin(38)*7=11.4
Hope it helps
6 0
3 years ago
Lines land m are parallel lines cut by the transversal line t Which angle is congruent to 1?
Olenka [21]

Answer

D. Angle 8

Step-by-step explanation:

7 0
3 years ago
What is the value of 4 to the power of -3​
Flauer [41]

Answer:

0.015625

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
3 years ago
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