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3 years ago

Find the area of a square with the side lengths of (1/2x+2)

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

8 0

Answer: There are no like terms

Step-by-step explanation:

You might be interested in

Which statements about the factors of the terms in the expression 20 a + 15 a b + 24 b are true? Select three options.

ExtremeBDS [4]

Answer:

Following are the true statements

2. The factors common to 20a and 15ab are 1, 5, and a.

3. The factors common to 20a and 24b are 1, 2, and 4.

5. The GCF of the expression is 1

Step-by-step explanation:

Expression is 20a + 15ab + 24b

Now lets have a look at each of the options provided!

1. The factors common to 20a and 15ab are 1, 5, a, and b.

False

As you can see there is no b in 20a term only 1,5,a are common hence it is false.

2. The factors common to 20a and 15ab are 1, 5, and a.

True

The terms 20a and 15ab are divisible by 1,5,a hence it is true.

3. The factors common to 20a and 24b are 1, 2, and 4.

True

The terms 20a and 24b are divisible by 1,2,4 hence it is true

4. The GCF of the expression is ab.

False

20a + 15ab + 24b

As you can see ab is not common in all of the terms hence it cannot be greatest common factor

5. The GCF of the expression is 1

True

Factor of 20 are: 2,2,5,1

Factor of 15 are: 3,5,1

Factor of 24 are: 2,2,2,3,1

As you can see the only common factor among all the terms is 1 hence GCF is 1.

5 0

3 years ago

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

6 0

3 years ago

Part 1:

Gnom [1K]

P = 2(L + W)
L = 4/3W

P = 2(4/3W + W) <=== part 1 is D

when P = 28
28 = 2(4/3W + W)
28/2 = 4/3W + 3/3W
14 = 7/3W
14 / (7/3) = W
14 * 3/7 = W
42/7 = W
6 = W....width is 6 inches

L = 4/3W
L = 4/3(6)
L = 24/3
L = 8....length is 8 inches

A = L * W
A = 8 * 6
A = 48 in^2 <==== part 2

7 0

3 years ago

I NEED HELP IN SPANISH PLEASE

valentina_108 [34]

I can help you in spanish

7 0

3 years ago

DUE TOMORROW PLEASE HELP

bija089 [108]

Answer:

This might help...

Step-by-step explanation:

To the nearest whole number, what is the percentage increase in volume? Explanation: To find the percentage difference, you merely subtract the start value from the end value and divide by the start.

5 0

3 years ago