What is W in this equation -w–11≤w–5
1 answer:
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Hey there! I'm happy to help!
First, let's multiply the numerators. We will put q+5 in parentheses so we can multiply it by 4q.
4q(q+5)
We use the distributive property to undo the parentheses.
First, we multiply 4q by q.
4q×q=4q²
And we multiply 4q and 5.
4q×5=20q
So, our numerator right now is 4q²+20q.
Now, for the denominators.
2(q+4)
We do 2 by q.
2×q=2q
And 2×4, which is 8.
So, our denominator is 2q+8.
Right now, our fraction is , and this is your correct answer. However, we can simplify it a bit more. We can divide the 4 by 2, q² by q, and simplify the 20 and the 8.
4/2=2
q²/q=q
20/8=5/2
Now, our final product is (2q+5)/2
But, mark down your answer as because that is technically correct.
Have a wonderful day! :D
<u>answer (in words)</u>
FALSE. the coordinate pair (5, 2) is not a solution to the equation . in order to figure out whether or not the statement is true or false, plug the
and
values from the coordinate pair (5, 2) into the given equation,
. if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.
<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>
<u>answer (algebraic/steps for solving)</u>
first, plug in 5 for in the equation
.
⇒
then plug in 2 for .
⇒
now your equation is . all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.
⇒
multiply 3 · 2.
⇒
add 10 + 6.
⇒
16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation . in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.
i hope this helps! have a great rest of your day <3