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4 years ago

The measure of angel b

Mathematics

1 answer:

defon4 years ago

3 0

Angle b is 130 degrees.

180-50=130

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4 - x is greater than 8.6<br>solve for x

ollegr [7]

The answer is any numbers larger than -4, not include -4

4 0

3 years ago

Analyze the diagram below and complete the instructions that follow.

bija089 [108]

Given:

ABC is a right triangle.

Opposite of C = AB = 6

Adjacent of C = BC = 8

Hypotenuse = AC = 10

To find:

The value of sin C.

Solution:

Using basic trigonometric ratio formula:

$$\sin \theta = \frac{\text{Opposite of }\theta}{\text{Hypotenuse}}$

$$\sin C = \frac{\text{Opposite of C}}{\text{Hypotenuse}}$

$$\sin C = \frac{AB}{AC}$

$$\sin C = \frac{6}{10}$

Cancel the common factors.

$$\sin C = \frac{3}{5}$

The value of sin C is $\frac{3}{5}$ .

7 0

3 years ago

The estimated insurance loss from a hurricane was $18.218.2 billion. This was $12.412.4 billion more than the loss from a tsun

Mashcka [7]

Answer:

If you are asking about the difference between the two, the difference is $5,805.80

Step-by-step explanation:

5 0

3 years ago

Find the equation of the line parallel to the given line that passes through the point

Luda [366]

A) parallel, same slope
Y = 3x + b
9 = 3(5) + b
9 = 15 + b, b = -6
Equation: y = 3x - 6x

B) y = -7x + b
11 = -7 + b, b = 18
Y = -7x + 18

c) y = 9x + b
-16 = 18 + b, b = -34

d) y = -x + b
9 = 2 + b, b = 7
Y = -x + 7

Try the rest on your own

3 0

3 years ago

Read 2 more answers

AC=36cm, and BC=27cm. Verify that DE\\AB.

emmasim [6.3K]

Answer:

$\overline {DE} \parallel \overline{AB}$ because $\frac{EC}{DC} = \frac{AC}{BC}$ .

Step-by-step explanation:

According to the Theorem of Thales and definition of proportionality, $\overline {DE} \parallel \overline{AB}$ if and only if $\frac{EC}{DC} = \frac{AC}{BC}$ . If we know that $EC = 15\,cm$ , $DC = 20\,cm$ , $BC = 36\,cm$ and $AC = 27\,cm$ , then we have the following result:

$\frac{15\,cm}{20\,cm} = \frac{27\,cm}{36\,cm}$

$\frac{3}{4} = \frac{3}{4}$

Hence, $\overline {DE} \parallel \overline{AB}$ .

4 0

3 years ago