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almond37 [142]
3 years ago
10

Find the complex zeros of

E%7B2%7D%20%20%2B%2059x%20-%2087" id="TexFormula1" title=" f(x) = {x}^{3 } - 13 {x}^{2} + 59x - 87" alt=" f(x) = {x}^{3 } - 13 {x}^{2} + 59x - 87" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
timama [110]3 years ago
6 0

f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3)  - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\

\\\implies x =3~~ \text{ or} ~~ x =5 \pm 2i\\\\\text{Hence the complex roots are,}~ 5- 2i ~~ \text{and} ~~5 + 2i

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trasher [3.6K]
First, let's put the second equation, <span>x-2.23y+10.34=0, in terms of y:
x - 2.23y +10.34 = 0   
2.23y = x + 10.34
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Now we can substitute the right side of this equation for y in the first equation
</span><span>y=2x^2+8x
.45x + 4.64 = 2x^2 + 8x
Turn it into a quadratic by getting 0 on one side:
2x^2 + 8x - .45x - 4.64 = 0
2x^2 + 7.55x - 4.64 = 0 Divide both sides by 2
x^2 + 3.76x - 2.32 = 0
x =( -b +/- </span>√(b² - 4ac) ) / 2a
x =( -3.76 +/- √(14.14 + 9.28)) ÷ 2
x = .54 or -4.31

Plug the x values into y = .45x + 4.64
y = .45 (.54) + 4.64
y = 4.88 when x= .54

y = .45 (-4.31) + 4.64
y = 2.70 when x= -4.31

Solution set:
{ (0.54, 4.88) , (-4.31, 2.70) }
8 0
3 years ago
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LenKa [72]

Hey there!

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Explanation:

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Answer:

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Step-by-step explanation:

For the first diagram,

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For the second diagram;

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