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3 years ago

Find the complex zeros of

E%7B2%7D%20%20%2B%2059x%20-%2087" id="TexFormula1" title=" f(x) = {x}^{3 } - 13 {x}^{2} + 59x - 87" alt=" f(x) = {x}^{3 } - 13 {x}^{2} + 59x - 87" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

timama [110]3 years ago

6 0

$f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3) - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\$

$\\\implies x =3~~ \text{ or} ~~ x =5 \pm 2i\\\\\text{Hence the complex roots are,}~ 5- 2i ~~ \text{and} ~~5 + 2i$

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