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Vlad1618 [11]
3 years ago
10

The graph of the function C(x) = −0.34x2 + 12x + 62 is shown. The function models the production cost, C, in thousands of dollar

s for a tire company to manufacture a tire, where x is the number of tires produced, in thousands:
graph of a parabola opening down passing through points negative 4 and 57 hundredths comma zero, zero comma 62, 1 and 12 hundredths comma 75, 17 and 65 hundredths comma 167 and 55 hundredths, 34 and 18 hundredths comma 75, and 39 and 87 hundredths comma zero

If the company wants to keep its production costs under $75,000, then which constraint is reasonable for the model?

−4.57 ≤ x ≤ 39.87
1.12 ≤ x ≤ 34.18
−4.57 ≤ x ≤ 1.12 and 34.18 ≤ x ≤ 39.87
0 ≤ x < 1.12 and 34.18 < x ≤ 39.87

Mathematics
1 answer:
Virty [35]3 years ago
7 0

Answer:

0 ≤ x < 1.12 and 34.18 < x ≤ 39.87

Step-by-step explanation:

Let

x ----> is the number of tires produced, in thousands

C(x) --->  the production cost, in thousands of dollars

we have

C(x)=-0.34x^{2} +12x+62

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The graph in the attached figure

we know that

Looking at the graph

For the interval [0,1.12) -----> 0\leq x

The value of C(x) ----> C(x) < 75

That means ----> The production cost is under $75,000

For the interval (34.18,39.87] -----> 34.18 < x\leq 39.87

The value of C(x) ----> C(x) < 75

That means ----> The production cost is under $75,000

Remember that the variable x (number of tires) cannot be a negative number

therefore

If the company wants to keep its production costs under $75,000 a reasonable domain for the constraint x is

0 ≤ x < 1.12 and 34.18 < x ≤ 39.87

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Mrs. Levi's class raised $217.35 in one-time donations for the library's new book collection. The class also had 4 people pledge
nexus9112 [7]

Answer: $817.35

Step-by-step explanation:

150x4 = 600

600+217.35 = 817.35

7 0
3 years ago
Write a recursive formula for the sequence
Over [174]

Answer:

The answer is:O f(1) = 10, f(n) = f(n − 1) + 2, for n > 1

Step-by-step explanation:

f1=10 because the first number is 10. then f(n)=f(n-1)+2 for N because it goes up 2 every time.

3 0
3 years ago
HELP ASAP PLEASE I NEED ANS N SOLUTION
Blababa [14]

Given:

A bowl contains 25 chips numbered 1 to 25.

A chip is drawn randomly from the bowl.

To find:

The probability that it is

a. 9 or 10?

b. even or divisible by 3?

c. divisible by 5 and divisible by 10?

Solution:

a. We have,

Number of total chips = 25

Favorable out comes are either 9 or 10. So,

Number of favorable outcomes = 2

The probability that the selected chip is either 9 or 10 is:

\text{Probability}=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}

\text{Probability}=\dfrac{2}{25}

Therefore, the probability that the selected chip is either 9 or 10 is \dfrac{2}{25}.

b. The numbers that are even from 1 to 25 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24.

The numbers from 1 to 25 that are divisible by 3 are 3, 6, 9, 12, 15, 18, 21, 24.

The numbers that are either even or divisible by 3 are 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24.

Number of favorable outcomes = 16

The probability that the selected chip is either even or divisible by 3 is:

\text{Probability}=\dfrac{16}{25}

Therefore, the probability that the selected chip is either even or divisible by 3 is \dfrac{16}{25}.

c. The numbers from 1 to 25 that are divisible by 5 are 5, 10, 15, 20, 25.

The numbers from 1 to 25 that are divisible by 10 are 10, 20.

The numbers that are divisible by both 5 and 10 are 10 and 20.

Number of favorable outcomes = 2

The probability that the selected chip is divisible by 5 and divisible by 10 is:

\text{Probability}=\dfrac{2}{25}

Therefore, the probability that the selected chip is divisible by 5 and divisible by 10 is \dfrac{2}{25}.

5 0
2 years ago
What are the minimum, first quartile, median, third quartile, and maximum of the data set? PLEASE Show your work.
Schach [20]
54 55 59 61 61 62 68 70 72
First put your numbers in order from least to greatest. This shows your minimum is 54 and maximum is 72.
In the middle of the data set is 61.

54 55 59 61. 61. 62 68 70 72

To find the first qaurtile only use the numbers before rhe median (54 55 59 61) and find the median of that. Since 55 and 59 are both in the middle add them both and divide by two to find the middle lf those two numbers. You should get 57. So 57 is the first quartile.

Do the same steps with the numbers after the meadian for your third quartile. You should get 69 as your answer for the third quartile.
7 0
2 years ago
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In an all boys school, the heights of the student body are normally distributed with a mean of 71 inches and a standard deviatio
Vika [28.1K]

Answer: the interval of heights that represents the middle 95% of male heights from this school is between 66 inches and 76 inches.

Step-by-step explanation:

Let x be a random variable representing the heights of males from this school. With the mean and standard deviation given, then the Empirical Rule says the that

1) About 68% of the x values lie between 1 standard deviation below and above the mean.

2) About 95% of the x values lie between 2 standard deviations below and above the mean.

3) About 99.7% of the x values lie between 3 standard deviations below and above the mean.

From the information given,

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Standard deviation = 2.5 inches

We want to determine where 95% of x values lies. This is 2 standard deviations from the mean Therefore,

2 standard deviations = 2 × 2.5 = 5 inches

The heights are

71 - 5 = 66 inches and

71 + 5 = 76 inches

7 0
2 years ago
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