If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3
Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23
You are to graph <span>y = |1.6x – 2| – 3.2. I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).
Let's rewrite </span><span>y = |1.6x – 2| – 3.2 by factoring 1.6 out of |1.6x - 2|:
</span><span>y = 1.6*|x – 2/1.6| – 3.2
This tells us that the vertex of </span><span>y = |1.6x – 2| – 3.2 is at (2/1.6, -3.2). If you need an explanation of why this is, please ask.
Plot the vertex at (1.25, -3.2).
Find the y-intercept: Let x = 0 in </span><span>y = |1.6x – 2| – 3.2 and find y:
y = 2-3.2 = -1.2
The y-intercept is located at 0, -1.2)
Plot this y-intercept.
Now draw a straight line from the vertex to this y-intercept. Reflect that line across the y-axis to obtain the other half of the graph.</span>
Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .
To Find : The correct option between the given ones . To write the compound inequality with integers .
Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .
⇒ 19 ≥ t + 18 .
⇒ t + 18 ≤ 19 .
⇒ t ≤ 19 - 18 .
⇒ t ≤ 1 = 1 ≥ t . ..................(i)
⇒ t + 18 ≥ 11 .
⇒ t ≥ 11 - 18.
⇒ t ≥ -7 . ....................(ii)
<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>
This means that t is less than or equal to 1 but greater than or equal to (-7) .
Answer:
90
Step-by-step explanation: 9 + 6 = 15
So, then you would multiply 15 x 6 which equals 90
Answer:
Step-by-step explanation:
d = dimes and a = quarters
0.10d + 0.25a > = 3 (thats greater then or equal) <===
