Tom and Sara are 12, and Andrew is 4
The given function is

i) We factor the numerator to obtain;

The vertical asymptote is where the denominator is zero.
V.A: 
ii) The roots are the zeros of the numerator;
Roots:



iii) At y-intercept
.
Put
into the function and solve.



Y-int: 
iv) Horizontal asymptote.
This is an improper rational function.
It has no horizontal asymptote.
v) Holes:
The given rational function has no common factors in both the numerator and the denominator.
Therefore the function has no holes.
6) For oblique Assymptote, we divide using lond division or synthetic division;
1 -1 -2
5| <u> 5 20</u>
1 4 18
The quotient is 
The oblique asymptote is

Answer:
The age of Sue could be 7 years
Step-by-step explanation:
Jenny is 8 years older than twice her cousin Sue's age.
The first equation will be :
J = 8 + 2S ---------(1)
The sum of their ages is less than 32.
The second equation will be :
J + S < 32 ----------------(2)
Now rearrange both equations :
8 + 2S + S < 32
3S < 32 - 8
3S < 24
S < 24/3
S < 8
S = 7
The age of Sue could be 7 years.
Answer: 1:45
Step-by-step explanation: If Tom left his house at 1:00 and it took him 45 minutes to get the pool, adding 45 minutes to 1:00 would make his arrival time 1:45. Therefore, he arrived at the pool club at 1:45. Have a great day!
Answer: The answer is given below.
Step-by-step explanation: The given circles are:
Circle 1: centre (2, 3) and radius 4
Circle 2: centre (2, 3) and radius 12.
The equations of circle 1 and circle 2 are respectively given as :

These two circles are drawn on the graph as shown in the attached figure.
We can easily see that the Circle 2 is a dilation of Circle 1 with a scale factor

Thus, the two circles are similar.