Question

Wilma is 5 times as old as yvonne. in ten years, yvonne's age will be a third of wilma's age. how old are they now?

Answer 1

Using a system of equations, it is found that Wilma is 50 years old and Yvonne is 10 years old.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

• Variable x: Wilma's age.

• Variable y: Yvonne's age.

Wilma is 5 times as old as yvonne, hence:

x = 5y.

In ten years, yvonne's age will be a third of wilma's age, hence:

$y + 10 = \frac{1}{3}(x + 10)$

Since x = 5y:

$y + 10 = \frac{1}{3}(x + 10)$

$y + 10 = \frac{1}{3}(5y + 10)$

3y + 30 = 5y + 10

2y = 20.

y = 10.

Then:

x = 5y = 5 x 10 = 50.

Wilma is 50 years old and Yvonne is 10 years old.

More can be learned about a system of equations at brainly.com/question/24342899

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