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SCORPION-xisa [38]
4 years ago
12

Please help asap! Will give brainliest! Please answer correctly! No guessing!

Mathematics
2 answers:
weqwewe [10]4 years ago
4 0

Answer:

Option D

Step-by-step explanation:

I solved in the picture

Hope this helps ^-^

Deffense [45]4 years ago
4 0

Answer:

5^8 / 9^8

Step-by-step explanation:

(a/b) ^c = a^c / b^c

(5/9)^8

5^8 / 9^8

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In a dilation with a scale factor of 3/4 , the image is ___________ the pre image
adelina 88 [10]
 A is the correct choice
4 0
3 years ago
During second period, Kiera completed a grammar worksheet. Of the 90 questions, she got 70% right. How many questions did Kiera
ANEK [815]

Answer:

we conclude that Kiera got the right 63 questions.

Step-by-step explanation:

Total questions = 90

The percentage of correct question = 70%

Using the formula

The number of correct questions = 70% of 90

                                                         = [70/100] × 90

                                                          = 0.7 × 90

                                                           = 63

Therefore, we conclude that Kiera got the right 63 questions.

7 0
3 years ago
10x-2y=18 8x=y solve by substitution
lana [24]

Answer:

x = -1 and y = 18

Step-by-step explanation:

Given the system of equations

y + 8x = 10... 1

2y - 4x = 40 ... 2

From 1; y = 10-8x

Substitute into 2;

2(10-8x) - 4x = 40

20 - 16x - 4x = 40

20 - 20x = 40

-20x = 40 - 20

-20x = 20

x = -1

Recall that y = 10-8x

y = 10 - 8(-1)

y = 10 + 8

y = 18

therefore your answer is  x = -1 and y = 18

4 0
3 years ago
Read 2 more answers
Can someone simplify this for me and the answer I don’t know help quickly!!!
Vinil7 [7]

Answer:

9/10

Step-by-step explanation:

8 0
3 years ago
Calculate the volume of a cuboid with length 5.6m breadth 4.1m, height 3.4m
lidiya [134]

Answer:  78.064 cubic meter

Step-by-step explanation:

volume of a cuboid=length × breadth × height.

                                =5.6*4.1*3.4

                                =78.064 cubic meter

6 0
3 years ago
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