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OverLord2011 [107]
3 years ago
14

Victor Malaba has a net income of $1.240 per month if he spends $150 on food . $244 on a car payment $300 on rent and $50 on sav

ings what percent of his net income can he spend on others things?
Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0
1249 (is your net income) 

1240-150 = 1090 - 244 = 846 - 300 = 546 - 50 = 496

$496 is the amount that can be spent on other things.
496 / 1249 = .397 (.40% rounded)

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Solve each system of linear equations by substitution.
Naddik [55]
3x-2(2x-7)=9 \\ 3x-4x+14=9 \\ -x+14=9 \\ -14\ \ \ \ -14 \\ -x=-5 \\ /-1/-1 \\ \ \ x=5
3 0
2 years ago
Read 2 more answers
-2(4a+4b)+5a&gt;-35<br> Solve the inequality
Amiraneli [1.4K]

Step-by-step explanation:

-2 (4a + 4b) + 5a > -35

-8a -8b + 5a > -35

-3a -8b > -35

for a

-3a > -35 + 8b

a < -35 + 8b ÷ -3

a < 35 - 8b ÷ 3

for b

-3a - 8b > -35

-8b > -35 + 3a

b < -35 + 3a ÷ -8

b < 35 - 3a ÷ 8

5 0
2 years ago
A production process is checked periodically by a quality control inspector. the inspector selects simple random samples of 30 f
777dan777 [17]

Answer:

Population Mean = 2.0

Population Standard deviation = 0.03

Step-by-step explanation:

We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.

Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.

Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.

So,   Mean, \mu = \frac{1.9+2.1}{2} = 2.0

Therefore, mean for the population of products produced with this process is 2.

Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.

             z = -1.6449 {from z % table}

We know that z formula is given by ;  

                Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

              -1.6449 = \frac{1.9 - 2.0}{\frac{\sigma}{\sqrt{n} } }     ⇒  \frac{\sigma}{\sqrt{n} }  = \frac{-0.1}{-1.6449}  

                                           ⇒ \sigma = 0.0608 * \sqrt{30}  {as sample size is given 30}

                                           ⇒ \sigma = 0.03 .

Therefore, Standard deviation for the population of products produced with this process is 0.0333.

7 0
3 years ago
A. 25<br><br>B. 40<br><br>C. 250<br><br>D. 400<br><br>Help me please and tha k you​
masha68 [24]
A your very welcome
7 0
3 years ago
SOMEONE PLEASE HELP ME IM STRESSED OUT I’ll GIVE OUT BRAINLIEST PLEASE DON’T ANSWER IF YOU DON’T KNOW
evablogger [386]

Answer:

Number 7: 40%

Number 8: 75%

Step-by-step explanation: Hope i helped mate

4 0
2 years ago
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