I hope this helps you
y=x^2-10x+35
y=x^2-10x+25+10
y-10=(x-5)^2
y=(x-5)^2+10
h= -(-5)=5
k =10
Answer:
Step-by-step explanation:
Apply exponent rule 
:
Factor out common factor 
:
<span>1, 7, 23, 161 is what can go into 161</span>
The solution for the given system of equations (x,y) is (-1/2, -5/2).
<u>Step-by-step explanation:</u>
The given system of equations are :
x - y = 2 ------(1)
x + y = -3 -------(2)
To solve the system of equations, you can use elimination method.
In this method, the first step is followed by adding both the equations.
x - y = 2
(+) <u>x + y = -3 </u>
<u>2x = -1 </u>
⇒ 2x = -1
divide by 2 on both side, to get x value.
⇒ x = -1/2
The value of x is -1/2
The second step is to substitute x = -1/2 in any of the two equations.
Put x = -1/2 in equation (1),
⇒ -1/2 -y = 2
Cross multiply the denominator 2 on both sides,
⇒ -1-2y =4
Add 1 on both sides,
⇒ -2y = 4 + 1
⇒ -2y = 5
Divide by -2 on both sides,
⇒ y = -5/2
The value of y is -5/2
The solution to the system of equations is be given by (x,y).
Therefore, the solution is (-1/2, -5/2).
xy = 30
x - y = 1
x + y = 11
First, we need to consider factors of 30:
1, 2, 3, 5, 6, 10, 15, 30
Which two of these, subtracted, would equal 1?
5 and 6
6 x 5 = 30
6 - 5 = 1
6 + 5 = 11
