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Mazyrski [523]
3 years ago
11

I need help I just can’t get it

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer:A

Step-by-step explanation: because x + 0 is still x and y + 0 is still y

and it is equivalent

Hope this helped

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Order the following numbers from least to greatest.
Lyrx [107]

Answer: -53, -24, 0, 0, 18

Step-by-step explanation:

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What is 4x - 1 = 3x + 10 ?
AfilCa [17]

Answer:

x=11

Step-by-step explanation:

first add 1 to both sides and the -1 will cancel out. Your left with 4x=3x+11.

Then subtract 3x from both sides and you will be left with. x=11

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John earns $5.75 per hour. He worked 40.0 hours last week. What was the amount of his check?
ratelena [41]

Answer: 230


Step-by-step explanation:

Given: The amount earned by John in an hour= $5.75

If he worked 40.0 hours last week, then the amount he earned is given by:-

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Therefore, the amount of his check was 230.

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3 years ago
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The length of a rectangle is 8 more than the width of the rectangle. The perimeter of the rectangle is 40 centimeters. Write and
Arturiano [62]

Answer:

the lenth of a rentangle is 8

Step-by-step explanation:

4 0
3 years ago
Calculate the distance between each line and the point. round your answer to one decimal place.
Dmitry [639]

                                     Solving Equation A

Given the equation A

y=4x-2

and point (-3, 3)

The distance from the point (x₀, y₀) to the line Ax+By+C=0 is given by

d=\frac{\left|Ax_0+By_0+C\right|}{\sqrt{A^2+B^2}}

To apply this formula, we first need to express the line in standard form

y=4x-2

4x-y-2=0

After substituting: A=4, B=-1, C=2, x₀=-3, y₀=3

d=\frac{\left|\left(4\right)\left(-3\right)+\left(-1\right)\left(3\right)+\left(-1\right)\right|}{\sqrt{4^2+\left(-1\right)^2}}

d=\frac{\left|-12-3-2\right|}{\sqrt{4^2+\left(-1\right)^2}}

d=\frac{17}{\sqrt{4^2+\left(-1\right)^2}}

d=\sqrt{17}

d=4.1 units

Therefore, the distance between the line y = 4x - 2 and the point (-3, 3) will be:

  • d=4.1 units

                                             Solving Equation B

Given the equation B

y = -x + 5

and point (-1, -2)

The distance from the point (x₀, y₀) to the line Ax+By+C=0 is given by

d=\frac{\left|Ax_0+By_0+C\right|}{\sqrt{A^2+B^2}}

To apply this formula, we first need to express the line in standard form

y = -x + 5

x+y-5=0

After substituting: A=4, B=1, C=-5, x₀=-1, y₀=-2

d=\frac{\left|\left(1\right)\left(-1\right)+\left(1\right)\left(-2\right)+\left(-5\right)\right|}{\sqrt{1^2+\left(1\right)^2}}

d=\frac{\left|-1-2-5\right|}{\sqrt{1+1}}

d=\frac{\left|-8\right|}{\sqrt{2}}

d=\frac{8}{\sqrt{2}}

d=4\sqrt{2}

d=5.7 units

Therefore, the distance between the line y = -x + 5 and the point (-1, -2) will be:

  • d=5.7 units
8 0
3 years ago
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