Combine like terms: x^3+x^3 = 2x^3
2x^2
-x
-10
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(f+g)(x) = 2x^3 + 2x^2 - x - 10 (answer)
9^6 is that number in exponential form.
Suppose the three sides are a, b, and c, with c being the longest, a being the shortest
first equation: c=(a+b)-66
second equation: 2a=c-55=> c=2a+55
plug c=2a+55 into the first equation: 2a+55= a+b-66 => b=a+121
a+b+c=a+(a+121)+(2a+55)=7272 =>4a+176=7272 =>a=1774
a=1774, b=1895, c=3603
It looks like the given equation says
When <em>x</em> = 0, you have
Differentiating both sides with respect to <em>x</em> gives
That is, the derivative operator distributes over sums, and the derivative of a constant is 0; apply the product rule on the first term and chain rule on the second; then use chain rule one more time.
Now plug in <em>x</em> = 0 and <em>y</em> = 5, and solve for <em>y'</em> :
Answer:
$5.75
Step-by-step explanation:
Joshua paid $9.10 for a bag and has $16.25 left
Now let's find out how much Joshua had before spending on a bag. To do this, we simply sum up the cost of the bag and how much Joshua had lefyt
9.10 + 16.25
=$25.35
Since Joshua and Shopping had the same amount, Shuping also had $25.35
To get the cost of the pen, we subtract the amount Shuping had left after purchasing the pen
This gives;
25.35 - 19.60
=$5.75