Question

George had one sheet of paper. He cut it into 6" x 5", and 3" x 6". What were the dimensions and total area of his original sheet of paper explain your answer

Answer 1

Answer:

Therefore the dimension of the paper were 9"×11".

Therefore the area of the sheet is  99   square inches.

Step-by-step explanation:

Length: Usually the longer side of a rectangle is known as the length of the rectangle.

Breadth: Comparatively the shorter side of a rectangle is known as the breadth of the rectangle.

Dimension: The length of sides of a quadrilateral is known as the dimension of the quadrilateral.

Rectangle:

• The parallel sides are equal.
• The diagonals cut to each other at their mid-point.
• Sum of all four angle is 360°.
• Each side of the rectangle cuts each other at 90°.

If the dimension of a rectangle is written as a"×b"

It means a is the length of the rectangle in inches and it means b is the breadth of the rectangle in inches.

Inches is denoted by "

George cuts a paper into 6"×5" and 3"×6"

6"×5"⇒ the length is 6"  and breadth is 5"

3"×6" ⇒ the length is 3"  and breadth is 6"

                    ____+_______________+____

Total length of

paper  is     (6"+3")=9"   and breadth is (5"+6")=11"

Therefore the dimension of the paper were 9"×11"

Area of rectangle is = length×breadth

                                 = (9×11) square inches.

                                =99   square inches

Therefore the area of the sheet is  99   square inches.

Answer 2

Answer:$l={8}'' ,b={6}''$,$l={6}'' ,b={8}''$

and area is$=48$ inch square

Step-by-step explanation:

area of sheet$=l\times b$

area of sheet first$={6}''\times {5}''$

$=30$ inch square

area of sheet second$={3}''\times {6}''$

$=18$ inch square

total area of both sheet$=30+18$

$=48$ inch square

area of sheet$=l\times b$

$=48$ inch square

$l={6}'' ,b={8}''$

or

$l={8}'' ,b={6}''$

perimeter of sheet

$=2\left ( l+b \right )$

$=2(6+8)$

$={28}''$