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Katarina [22]
3 years ago
6

|2x-3|=2 please answer this by Wednesday. I have no idea how to solve this. I wasn't paying attention

Mathematics
2 answers:
Sholpan [36]3 years ago
3 0

Answer:

x=2.5

Step-by-step explanation:

Alja [10]3 years ago
3 0
Ok so in order to solve you need to get the variable by itself, in this case it is x. The first thing you do is add or subtract. You add 3 to the left side to cancel it and whatever is done to one side must be done to the other which is why you add 3 to 2. Now the equation is 2x=5. In order to get the x by itself you must divide by 2. When you divide 2x by 2, the 2 will cancel out. Again, you have to do the same thing to the other side. 5 divided by 2 is 5/2, so x=5/2 is your answer. To check, plug in 5/2 for x. 2 times 5/2 is 5 and 5-3 is 2. 2=2 so the answer is correct. Hope this helped!

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Need help with homework
motikmotik

We have two points describing the diameter of a circumference, these are:

\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}

Recall that the equation for the standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Now, we replace and solve:

\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}

The center of the circle is (-8,-7), so:

\begin{gathered} h=-8 \\ k=-7 \end{gathered}

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

r^2=\Delta x^2+\Delta y^2

In this case, we will solve the delta with the center coordinate and the B coordinate.

\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}

Therefore, the equation for the standard form of a circle is:

\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}

In conclusion, the equation is the following:

(x+8)^2+(y+7)^2=25

4 0
1 year ago
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