So to factor
factor out a x+z
(x+z)(x^2-xz+z^2)
the factors are
x+z and x^2-xz+z^2
Answer:
Very Simple!
Step-by-step explanation:
Just use the distance formula!
(I'm in a math class right now, so I have to keep it brief)
Distance Formula, example:
Just input the x and y values from A and B into here, and then that's it!
Hope this helps!
Happy Geometry!
Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
C . 250 cm^2
cause its the same
Interval notation
(-infinity sign, 1)
Set-builder notation
{x|x less than equal to 1}
