What is 38.3 minus -1.2?

1 answer:

6 0

(38.3 - -1.2) = 39.5

Anytime you have two minuses beside each other, you add.
If you have a plus sign in the middle, but one of the numbers is negative you subtract.

Hope that makes sense ! (:

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I need to Match each equation that represents each situation.

almond37 [142]

Step-by-step explanation:

this is quite easy, when you use just common sense and identify the right numbers and variable names.

they is nothing special needed, you don't even need to create the equations yourself.

$4.99 per pound. buys b pounds and pays $14.95.

14.95 = 4.99 × b

$4.99 per pound. buys b pounds and pays c.

this is exactly the same as before, just that this time the total amount is not given as a constant but as a variable.

c = 4.99 × b

d dollars per pound. buys b pounds and pays t.

the same as the 2 cases before, just now everything is a variable. no more constants, but otherwise the completely same structure and method.

t = d × b

earned $275, which is $45 more than Noah ("n").

$275 = n + $45

earned m dollars, which is $45 more than Noah ("n").

m = n + $45

earned m dollars, which is y dollars more than Noah (we are asked that Noah's earnings are now called "v").

here your teacher made a mistake.

sure, the only remaining answer is

v = m + y

but it is not correct. given the names of the prime and associated variables the correct answer would be

m = v + y or v = m - y

7 0

1 year ago

What is the unit rate for 16 ounces (pint) at $3.93?

Juli2301 [7.4K]

Answer:

25 cents/ounce

Step-by-step explanation:

The unit rate means how much is one of the thing you are working with. In this case, the unit rate of a pint (16 ounces) is how much just one ounce will cost. So divide $3.93 by 16

$3.93/16 = $0.245625

Since we're working with money, round to the nearest hundredth

Unit rate is $0.25 per ounce, or 25 cents per ounce

8 0

3 years ago

Read 2 more answers

Jessiah purchased 3 pairs of sneakers that cost d dollars- but

postnew [5]

Answer:

D-10

Step-by-step explanation:

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