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shtirl [24]
3 years ago
14

Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and

the median. Is Roger’s claim correct?
Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

No, the Roger’s claim is not correct.

Step-by-step explanation:

We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.

This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.

As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.

Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.

Hence, the mean will likely to change greatly when an outlier is added to a small data set.

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Find expressions for the partial derivatives of the following functions:
nlexa [21]

Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

* f(x), just like g(x), simply means/represents a function in X hence f'(x) means the differentiation of all X-terms in that function

6 0
3 years ago
alex has a 48 mile trail first half of the time he was biking twice as fast as the second half of the time if he spent 4 hours o
Irina-Kira [14]

Answer:

16 mph

Step-by-step explanation:

Givens:

4 hours total time

48 miles total distance

So our equation should look like this.

48 = 2x(2) + x(2)

Where x = speed second half of trip.

x = 8

x*2 = 16 mph

4 0
3 years ago
What is the exact area of a circle with a diameter of 18 feet
marin [14]
A = π r^2
A = 9^2 <span>π
</span>A = 81<span>π 

if using </span>π = 3.14 then

A = 3.14 x 81 = 254.47 ft^2

answer: 81π ft^2 or 254.47 ft^2

hope that helps
6 0
3 years ago
USE A MODEL Olivia and her brother William had a bicycle race. Olivia rode at a speed
Anni [7]

Answer:

Let the total distance Aileen ran be 'x'

Let the distance ran by Andrew be 'y'

Refer to graph attached for graphical representation of distance travelled by both.

Applying the formula,

distance=speed*time

x=20*t      Equation  1

y= 15*t       equation 2

Since it can be easily understood by the graph attached, that

x=150+y  equation 3

Now putting values of x and y in equation 3

20*t =150 +15*t.

5t= 150

t=30 seconds.

putting the values of t in both the equation 1 and 2

x=20t

=20*30

x  = 600 feet

So the distance ran by Aileen is 600 feet, whereas Andrew ran 450 feet.

Step-by-step explanation:

Do not mind the names just change them. I had the same question before with different names so that is why. Hope this helps:)

7 0
2 years ago
Rooter Plus charges a $25 service fee plus $40 per hour of work done. Is this a proportional or non-proportional relationship?
Dominik [7]

Answer:

Non-proportional; the rate of change is $40/hour

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u>and the line passes through the origin</u>

Let

x -----> the number of hours

y ----> The total charge in dollars

The equation of the line in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=40\ \$/h\\b=\$25

substitute

y=40x+25

This relationship is not proportional, because the line not passes through the origin

therefore

Non-proportional; the rate of change is $40/hour

5 0
3 years ago
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