Take note that they spent $18 afterwards having $28 on the card so they're spending money off the card so...
x-18=28
would be the equation for this and to solve do the following.
First add 18 to both sides making the equation.
x=46
A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.
We can use the Pythagorean formula to find the other leg of the right triangle.
a²+b²=c²
Where a and b are the legs of the triangle and c is the hypotenuse.
According to the given problem,
one leg: a= 5m and hypotenuse: c=13√5 m.
So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,
5²+b²=(13√5)²
25 + b² = 13²*(√5)²
25 + b² = 169* 5
25+ b² = 845
25 + b² - 25 = 845 - 25
b² = 820
b =√ 820
b = √(4*205)
b = √4 *√205
b = 2√205
b= 2* 14.32
b = 28.64
So, b= 28.6 (Rounded to one decimal place)
Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).
34% is the correct answer
Answer:
The area of the figure is 117m²
Step-by-step explanation:
In this problem, you have two shapes. One shape is a rectangle. The other shape is a triangle.
Area of a rectangle = b*h = 9*7 = 63
Area of a triangle =
(b*h) =
Since there are two triangles, you will multiply the area of the one triangle in the figure by 2.
27*2 = 54
Now, you add up the areas!
54 + 63 = 117
So, the area of the figure is 117m²
This is not seeing me clearly so that's why I can't able to help u.