The answer is 13.2 m.
Because we are only given the hypotenuse, adjacent, and theta measurements.
the opposite side is always opposite theta. In this case, theta is 39 degrees. The hypotenuse is always the slant of the triangle, so it is 17 m. And adjacent is obviously the only one left, in this case, it is x.
You have to use sin, cos, or tan for this problem. You would use cos because cos = adjacent /hypotenuse (x/17)
so you would do cos(39) times 17
x = cos(39) * 17
x = .777 * 17
x = 13.21
And it says round to the nearest tenth, so it is 13.2 m.
Hope this helps.
Hello from MrBillDoesMath!
Answer:
12 m n^2
Discussion:
3m * 4 * n * n = => 3* 4 = 12
12 m * n * n => as n*n = n^2
12 m n^2
Thank you,
MrB
The correct question is
<span>A country's people consume 6.3 billion pounds of candy (excluding chewing gum) per year. Express this quantity in terms of pounds per person per month. Note that the population of the country is 301 million.
we know that
1 billion------------------> 1000000000 </span><span>(Thousand </span>Million)=1 x 10<span>^9
</span><span>then
</span>6.3 billion pounds--------------> 6.3 x 10^9 pounds
[pounds of candy per person per year]=[6.3 x 10^9 pounds]/[301 x 10^6]
[pounds of candy per person per year]=20.93 pounds per person per year
[pounds of candy per person per month]=20.93/12=1.74 pounds per person per month
the answer is 1.74 pounds per person per month
The value of the composite function is (f/g)(5)= 26
<h3>How to evaluate the
composite function?</h3>
The functions are given as:
f(x) = x^2+1 and g(x) = x-4
To calculate the composite function, we use the following formula
(f/g)(x)= f(x)/g(x)
So, we have:
(f/g)(5)= f(5)/g(5)
Calculate f(5) and g(5)
f(5) = 5^2+1 and g(5) = 5-4
This gives
f(5) = 26 and g(5) = 1
Substitute f(5) = 26 and g(5) = 1 in (f/g)(5)= f(5)/g(5)
(f/g)(5)= 26/1
Evaluate
(f/g)(5)= 26
Hence, the value of the composite function is (f/g)(5)= 26
Read more about composite function at
brainly.com/question/10687170
#SPJ1
One twelths 1/12 try to find a commen denominator or use a caculator
