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pishuonlain [190]
3 years ago
7

Write in simplest form 3m⋅4⋅n⋅n​

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0

Hello from MrBillDoesMath!

Answer:

12 m n^2

Discussion:

3m * 4 * n * n  =                       => 3* 4 = 12

12 m * n * n                              => as n*n = n^2

12 m n^2

Thank you,

MrB

notsponge [240]3 years ago
4 0

Answer:

12 m n^2

Step-by-step explanation:

3m⋅4⋅n⋅n

Rearranging

3*4*m*n*n

Combine like terms

12 m n^2

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The table shows how the time it takes a train to travel between two cities depends on its average speed.
Ivahew [28]

Answer:

y=\frac{160}{x}

Step-by-step explanation:

The table shows how the time it takes a train to travel between two cities depends on its average speed.

function models the time, y, in hours, that it takes the train to travel between the two cities at an average speed of x miles per hour

y represents the time

and x represents the average speed

WE know distance = speed * times

LEts find the distance using the table

distance = 32* 5= 160

40*4= 160

50*3.2 = 160

Time = distance / speed

times is y , distance is 160  and speed is x

y=\frac{160}{x}

6 0
3 years ago
Read 2 more answers
Find the missing length
hram777 [196]

Answer:

15

Step-by-step explanation:

7 0
3 years ago
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What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?
liubo4ka [24]

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Step-by-step explanation:

To add or subtract 2 fractions, they must have same denominators, if they not do that

  • Find the Lowest common multiple of the two denominators (LCM)
  • Replace each denominator by it
  • Divide The LCM by each denominator and multiply the numerator of each fraction by its quotient

∵ ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} )

- Let us start with adding the like terms

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = (

∵ ( \frac{2}{5} x + \frac{1}{5} x ) have same denominators, then we can add them

∴ ( \frac{2}{5} x + \frac{1}{5} x ) = \frac{3}{5} x

∵  ( \frac{5}{8}  - \frac{1}{4} ) do not have the same denominators, then we must find

    LCM of 8 and 4

- The LCM of 8 and 4 is 8 because 8 is the first common multiple

   of 8 and 4

∵ LCM of 8 and 4 is 8

- Divide 8 by the denominator 4

∵ 8 ÷ 4 = 2

- Multiply the numerator of the fraction by 2

∴ \frac{1}{4}=\frac{2}{8}

∴  ( \frac{5}{8}  - \frac{1}{4} ) = ( \frac{5}{8} - \frac{2}{8} ) = \frac{3}{8}

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = \frac{3}{5} x +  \frac{3}{8}

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Learn more:

You can learn more about the fractions in brainly.com/question/2456302

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e
Bingel [31]
Assuming the series is

\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}

The series will converge if

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|

We have

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|

So the series will certainly converge if -1, but we also need to check the endpoints of the interval.

If x=1, then the series is a scaled harmonic series, which we know diverges.

On the other hand, if x=-1, by the alternating series test we can show that the series converges, since

\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0

and is strictly decreasing.

So, the interval of convergence for the series is -1\le x.
6 0
3 years ago
Find the​ fourth-degree polynomial function with zeros 4​, -4, 4i ​, and -4i . Write the function in factored form.
Iteru [2.4K]

Given:

A fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i .

To find:

The fourth-degree polynomial  function in factored form.

Solution:

The factor for of nth degree polynomial is:

P(x)=(x-a_1)(x-a_2)...(x-a_n)

Where, a_1,a_2,...,a_n are n zeros of the polynomial.

It is given that a fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i. So, the factor form of given polynomial is:

P(x)=(x-4)(x-(-4))(x-4i)(x-(-4i))

P(x)=(x-4)(x+4)(x-4i)(x+4i)

P(x)=(x-4)(x+4)(x^2-(4i)^2)           [\because a^2-b^2=(a-b)(a+b)]

On further simplification, we get

P(x)=(x-4)(x+4)(x^2-4^2i^2)

P(x)=(x-4)(x+4)(x^2+16)                [\because i^2=-1]

Therefore, the required fourth degree polynomial is P(x)=(x-4)(x+4)(x^2+16).

6 0
3 years ago
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