Ask question

Ask question

All categories

Anastaziya [24]

3 years ago

14

How do you use the slope to prove lines are parallel or perpendicular

1 answer:

zaharov [31]3 years ago

3 0

In order to find if two lines are parallel or perpendicular or neither, following rules are used:

If the slope of two lines is the same, the two lines will be parallel
If the product of slopes of two lines is -1, the two lines will be perpendicular to each other.
If none of the above two conditions is being satisfied, this mean lines are neither parallel nor perpendicular.

So the steps that must be followed are:

Find the slope of the given lines.
Use the values of the slope to check which of the above point is being satisfied and draw the conclusion accordingly.

You might be interested in

Why is looking at cash flow an important step in a good financial plan?

sergejj [24]

Cuz it can help you later on in the fuchure

8 0

3 years ago

For each fraction, write the equivalent percent. a. 6/100 b. 57/100 c. 357/100 d. 100/100

ddd [48]

Answer:

(A) 6%

(B) 57%

(C) 357%

(D) 100%

Step-by-step explanation:

(A) 6 / 100 = 6%

(B) 57 / 100 = 57%

(C) 357 / 100 = 357%

(D) 100 / 100 = 100%

5 0

3 years ago

Read 2 more answers

2(3x-5)<4x+6 as a word problem

Nastasia [14]

Answer: x<8

Step-by-step explanation:

3 0

3 years ago

I will Mark you as brainliest if you explain

Minchanka [31]

Answer:

x=0 or x=−4

Step-by-step explanation:

Let's solve your equation step-by-step.

(x+2)2=4

Step 1: Simplify both sides of the equation.

x2+4x+4=4

Step 2: Subtract 4 from both sides.

x2+4x+4−4=4−4

x2+4x=0

Step 3: Factor left side of equation.

x(x+4)=0

Step 4: Set factors equal to 0.

x=0 or x+4=0

x=0 or x=−4

8 0

3 years ago

A circle is shown. 2 raddi are drawn. A chord connects the points of the radii on the circle to each other to form a triangle. T

iragen [17]

Answer:

$(5\pi-11.6)ft^2$

Step-by-step explanation:

Given:

Length of radius of circle = 5 feets

Length of perpendicular bisector = 4 feets

To find:

Area of the shaded portion of the circle

Solution:

As OD is perpendicular bisector of AB,

$AB=2AD=2(2.9)=5.8\,\,feets$

$\angle ODA=90^{\circ}$

Area of $\Delta AOB$ = 1/2 (base) × (height) = $\frac{1}{2}\times 4\times 5.8=11.6$ square feets

Area of sector AOBC = $\frac{\angle AOB}{360^{\circ}}\pi(r^2)=\frac{72^{\circ}}{360^{\circ}}\pi(5^2)=5\pi$ square feets

Here, r denotes radius of circle

So,

Area of shaded portion = Area of sector AOBC - Area of $\Delta AOB$ = $(5\pi-11.6)ft^2$

3 0

3 years ago