The answer from my calculations is 32
The answer would be +3 since ur adding 3 every time
Answer:
I dont know if you meant to put the 6 as a 6 or a 16 but ill solve both
if it includes 16= -2=x
if it inclues 6- 3=x
Step-by-step explanation:
16=2-2x+10 you would combine the 10 and the 2
16=-2x+12 then you would minus the 12 from both sides
4=-2x then divide by -2 on both sides
-2=x
6=2-2x+10 Again combine the 10 and the 2
6=-2x+12 Then minus 12 from both sides
-6=-2x then divide the -2 from both sides
3=x
The correct question is:
What is the probability that 2 girls and 2 boys will be selected?
Solution:
Total number of students = 10
Ways to select a team of 4 students = 10C4 = 210
2 Boys can be selected from 6 boys in ways = 6C2 = 15
2 Girls can be selected from 4 girls in ways = 4C2 = 6
Number of ways to select 2 boys and 2 girls = 15 x 6 = 90
Probability of choosing 2 boys and 2 girls = 90/210 = 3/7
Thus, if 4 team members are selected, the probability of choosing 2 boys and 2 girls will be 3/7
