The domain of a function is the set of input or argument values for which the function is real and defined.
So, for the given function to be defined, we need to find the possible values for which the values of x makes the square root to be positive.
That is;
-9 -5x ≥ 0
Now, let's solve for x
Add 9 to both-side of the equation
-5x ≥ 9
Divide both-side by -5
x ≤ -9/5
Therefore, the domain of the function can be represented in interval notation as: ( - ∞ , -9/5]
No, it is not a function, since 6 is repeating itself and the x should never repeat if it’s a function.
Answer:
Step-by-step explanation:
The given circle has equation
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The equation of a circle with center (h,k) and radius r units is


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<h2>❖ Tip❖ :- </h2>
This is the equation that has its center at the origin with radius 4 units.
When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).