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alukav5142 [94]
4 years ago
15

Mr. Adams asked his students to write the chemical symbol for the element zinc. He wrote the students answers on the white board

. Which answer is correct?
Physics
1 answer:
suter [353]4 years ago
7 0
The symbol for the element zinc is Zn.
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When can hfc-134a become combustible in a mobile air conditioning system?
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The  mixture  of  HFc-134a with  high  concentration  of  air  at  raised  pressure    can  become  combustible  in  presence  of  a  ignition  source,  that  is  oxygen  enriched  environment.Thus  at  high  pressure  in a mobile  air  condition   led   to   combustible  of HFC-134a.
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There was an airplane crash, every single person on board died, but yet two people survived. How is this possible?
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If everyone died then the too people were not on the plane they were near by when the plane crashed and were not onbard.
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Why don't atoms get too close?
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Answer:

<h3>This tends not to happen, because atoms are composed of charged particles that interact at a distance. ... Since the electrons are around the outside of the atom, those are the things that first interact, and as they have the same charge, they repel one another.</h3>

A. The electrons from atom repel each other

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A hockey puck moves 22 meters northward, then 16 meters southward, and finally 4 meters northward.
xenn [34]

Answer:

Distance moved = 42 meters

Mag and Dir = 10 meters northward

Explanation:

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8 0
3 years ago
A friend of yours is loudly singing a single note at 412 Hz while racing toward you at 23.0 m/s on a day when the speed of sound
kobusy [5.1K]

Doppler Effect is required to solve the problem. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. The general formula of observed frequency, due to Doppler's effect is as follows,

f_0 = (\frac{v+v_0}{v-v_s})f_s

f_0 = Frequency observed by observer

v = Velocity of Sound

v_0 = Velocity of observer

v_s = Velocity of source

f_s = Frequency of source

PART A) Replacing our values we have that,

f_0 = (\frac{v+v_0}{v-v_s})f_s

f_0 = (\frac{344+0}{344-23})(412)

f_0 = 441.52Hz

PART B) Here the same procedure is performed but this time repeated in the opposite direction.

f_0 = (\frac{v+v_0}{v-v_s})f_s

f_0 = (\frac{344+23}{344-0})(420)

f_0 = 448.08Hz

4 0
3 years ago
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