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Rina8888 [55]
3 years ago
6

A bucket of water is being raised from a well using a rope. If the bucket of water has a mass of 6.2 kg, how much force (in N) m

ust the rope exert on the bucket to accelerate it upward at 1 m/s2
Physics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

6.2N force

Explanation:

According to Newton's second law of motion, force is equal to the product of the mass of a body and its acceleration. Mathematically,

Force = mass × acceleration

Given mass of bucket of water = 6.2kg

acceleration of the bucket = 1m/s²

Force exerted on the rope = 6.2 × 1

= 6.2N

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Examine the symbols below:
iris [78.8K]

Answer: Symbol A

Explanation:

The four symbols described here represent:

- Symbol A shows two dots and a line draw from one not connected to the other.  --> this is an open switch. A switch is component of a circuit that is used to open/close the circuit in order to interrupt/allow the flow of current through the circuit. In this case, the switch is open, since the line does not connect the second dot.

- Symbol B shows two dots and a line draw from one connected to the other.  --> this is the symbol used to represent the switch when it is closed, so it is a closed switch.

- Symbol C shows vertical lines in the pattern long, short, long, and short with a plus and minus symbol on it. --> this symbol represents a battery, which consists of two or more cells and provides the electromotive force that pushes the electrons along the circuit.

Therefore, the correct symbol representing the open switch is

Symbol A

6 0
3 years ago
Read 2 more answers
What is saturns most distinctive feature?
a_sh-v [17]
Its prominent ring system which is composed of primarily ice particles with smaller amounts of rocky detbris. Hope this helped!
6 0
3 years ago
How far does a car travel as it accelerates from 12 m/s to 18 m/s at 3 m/s??
yulyashka [42]

Answer:

Explanation:

I ASSUME you mean acceleration is 3 m/s²

v² = u² + 2as

s = (v² - u²) / 2a

s = (18² - 12²) / (2(3))

s = 30 m

to verify we can see that the acceleration time is

t = (18 - 12) / 3 = 2 s

s = 0 + 12(2) + ½(3)2² = 30 m

4 0
2 years ago
A 50 kg person steps off a diving platform that is 10 meters above the water below (Olympic height). With what speed do they hit
Nookie1986 [14]

Answer:

14 m/s

Explanation:

The following data were obtained from the question:

Mass = 50 kg

Initial velocity (u) = 0 m/s

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

The velocity (v) with which the person hit the water can be obtained as shown below:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 10)

v² = 0 + 196

v² = 196

Take the square root of both side

v = √196

v = 14 m/s

Therefore, he will hit the water with a speed of 14 m/s

5 0
3 years ago
A thin block of soft wood with a mass of 0.072 kg rests on a horizontal frictionless surface. A bullet with a mass of 4.67 g is
kozerog [31]

Answer:

v’= 279.66 m / s

Explanation:

We work this exercise using the conservation of the moment. For this we define the system formed by the two blocks, therefore the forces during the collision are internal of the action and reaction type.

Initial instant. Before the crash

        p₀ = m v₀ + 0

Final moment. After the crash

        p_f = m v + M v ’

how the tidal wave is preserved

       p₀ = p_f

       m v₀ = m v + M v ’

       v = \frac{m v_o - Mv'}{m}

let's calculate

       v ’= \frac{0.00467 \ 619 - 0.072 \ 22}{0.004676}

       v ’= \frac{2.89- 1.584}{ 0.00467}

       v ’= 279.66 m / s

4 0
3 years ago
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