<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
The answer is 6.55, because 42.6-(13.45+9.5)=19.65, and 19.65/3=6.55.
Answer:
x+3-5 i think
Step-by-step explanation:
"and" means add so x+3 and subtract 5
Answer:
x² - 4
Step-by-step explanation:
Step 1: Write expression
(x + 2)(x - 2)
Step 2: FOIL
x² + 2x - 2x - 4
Step 3: Combine like terms
x² - 4
Answer:
the 4th one ,hoped this help
