Answer:
Step-by-step explanation:
<h2><u>Part A</u></h2>
in interval ( 0 ; 2)
<h2><u>Part B</u></h2>
in interval (2; 4)
<h2><u>Part C</u></h2>
in interval (4 ; 6 )
<h2><u>Part D</u></h2>
The graph shows that at first the ball rises up ; and then it is seen that it goes down and loses height to zero , from which it can be concluded that the height after 10 seconds remains unchanged and therefore the height of the ball after 16 seconds will be zero
Matt could do one of the following arrangements;
2 rows of 8 CDs
4 rows of 4 CDs
Answer:
6.28571428571
Step-by-step explanation:
7 is the right answer(please rate 5.0 stars so i can help other people out thanks)
let's bear in mind that B is the midpoint and thus it cuts a segment into two equal halves.
![\bf \underset{\leftarrow \qquad \textit{\large 10x-6}\qquad \to }{\boxed{A}\stackrel{4x+2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{\underline{4x+2}}{\rule[0.35em]{10em}{0.25pt}\boxed{C}}} \\\\\\ AC=AB+BC\implies 10x-6=(4x+2)+(4x+2)\implies 10x-6=8x+4 \\\\\\ 2x-6=4\implies 2x=10\implies x=\cfrac{10}{2}\implies x= 5 \\\\[-0.35em] ~\dotfill\\\\ AC=(4x+2)+(4x+2)\implies AC=[4(5)+2]+[4(5)+2] \\\\\\ AC=22+22\implies AC=44](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7B%5Cleftarrow%20%5Cqquad%20%5Ctextit%7B%5Clarge%2010x-6%7D%5Cqquad%20%5Cto%20%7D%7B%5Cboxed%7BA%7D%5Cstackrel%7B4x%2B2%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20B%5Cstackrel%7B%5Cunderline%7B4x%2B2%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BC%7D%7D%7D%20%5C%5C%5C%5C%5C%5C%20AC%3DAB%2BBC%5Cimplies%2010x-6%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%2010x-6%3D8x%2B4%20%5C%5C%5C%5C%5C%5C%202x-6%3D4%5Cimplies%202x%3D10%5Cimplies%20x%3D%5Ccfrac%7B10%7D%7B2%7D%5Cimplies%20x%3D%205%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20AC%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%20AC%3D%5B4%285%29%2B2%5D%2B%5B4%285%29%2B2%5D%20%5C%5C%5C%5C%5C%5C%20AC%3D22%2B22%5Cimplies%20AC%3D44)
