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Neko [114]
3 years ago
14

The number 0.6064 represents the area under the standard normal curve below a particular z-score

Mathematics
1 answer:
nalin [4]3 years ago
5 0
Reference to a standard normal distribution table shows that for a cumulative probability of 0.6064 the z-score is 0.27.
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What are they?! Plz help!!!
Anika [276]

Answer

35 = 1,5,7,35


Step-by-step explanation:


5 0
4 years ago
E is the midpoint of Df, DE=2x+4, and EF=3x-1. Find all segment lengths
sertanlavr [38]
If E is the midpoint, DE and EF are equivalent.
2x+4=3x-1
4=x-1
5=x

Plug the value of x in
2(5)+4
14

3(5)-1
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14+14=28

Final answer: DE=14, EF=14, DF= 28
6 0
4 years ago
Which figure represents an undefined term?
Fudgin [204]
In geometry, the three undefined terms are: the point, the plane and the straight line.

Since all the given graphs represent lines,we will need to choose the straight line among them.

Straight line is a line that has no start and no end.

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Figures a and c are rays
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figure d is a straight line

Therefore, the correct choice is: D
8 0
4 years ago
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David worked seven hours and earned $117.25. If he earned $670, how many hours did he work?
arsen [322]

I believe the answer is 78557.5 hours

4 0
3 years ago
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In a survey of 329 people who attended a local professional soccer team’s most recent home game, 141 said that they were fans of
Verdich [7]

Answer: (0.3751,0.4821)

Step-by-step explanation:

Given : Level of significance : 1-\alpha:0.95

Then , significance level : \alpha: 1-0.95=0.05

Since , sample size : n=329 , i.e. a large sample (n<30).

Then we use z-test.

Using excel (by going in formulas for more statistics and then statistics), Critical value : z_{\alpha/2}=1.96

Also, the proportion of people said that they were fans of the visiting team :-

\hat{p}=\dfrac{ 141}{329}\approx 0.4286

The confidence interval for population proportion is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

0.4286\pm(1.96)\sqrt{\dfrac{0.4286(1-0.4286)}{329}}\\\\\approx0.4286\pm0.053\\\\=(0.4286-0.0534, 0.4286+0.053=(0.3751,\ 0.4821)

Hence,  a 95% confidence interval for the population proportion of attendees who were fans of the visiting team= (0.3751,0.4821)

4 0
3 years ago
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