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stealth61 [152]
3 years ago
14

David worked seven hours and earned $117.25. If he earned $670, how many hours did he work?

Mathematics
2 answers:
arsen [322]3 years ago
4 0

I believe the answer is 78557.5 hours

sertanlavr [38]3 years ago
3 0

Answer:

40 hours

Step-by-step explanation:

$117.25 / 7 hours = $16.75 an hour

$670 / $16.75 = 40 hours

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Identify the slope and the y-intercept of<br> the line with the given equation:<br> 2x+6y=12
Elza [17]

Answer:

The slope is -1/3 and the y-intercept is (0, 2).

Step-by-step explanation:

2x+6y=12

6y=12-2x

6y=-2x+12

y=-2/6x+12/6

y=-1/3x+2

y=mx+b where m=slope and b=y-intercept

5 0
2 years ago
Hose 1 in June took 45 mins to fill a pool of height of 20 inches and length 110 inches. Hose 2 in July took 15 mins to fill the
worty [1.4K]

Answer:

there isnt enough evidence to colclude an answer

Step-by-step explanation:

6 0
3 years ago
In the figure, the measure of angle 9 is 80 degrees and the measure of angle 5 is 68. Find the measure of each angle.
murzikaleks [220]

Answer/Step-by-step explanation:

Given:

m<9 = 80°,

m<5 = 68°

Lines w and v are parallel to each other.

m<1 = m<9 (corresponding angles theorem)

m<1 = 80°

m<2 + m<1 = 180° (linear pair)

m<2 + 80° = 180° (substitution)

m<2 = 180° - 80°

m<2 = 100°

m<3 = m<1 (vertical angles are congruent)

m<3 = 80°

m<4 = m<2 (vertical angles are congruent)

m<4 = 100°

m<6 + m<5 = 180° (linear pair)

m<6 + 68° = 180° (substitution)

m<6 = 180° - 68°

m<6 = 112°

m<7 = m<5 (vertical angles)

m<7 = 68°

m<8 = m<6 (vertical angles)

m<8 = 112°

m<10 = m<2 (corresponding angles)

m<10 = 100°

m<11 = m<9 (vertical angles)

m<7 = 80°

m<12 = m<10 (vertical angles)

m<12 = 100°

m<13 = m<5 (corresponding angles)

m<13 = 68°

m<14 = m<6 (corresponding angles)

m<14 = 112°

m<15 = m<13 (vertical angles)

m<15 = 68°

m<16 = m<14 (vertical angles)

m<16 = 112°

6 0
3 years ago
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
Find AuB and AnB for the sets A and B.<br> A={3, 4, 5, 6, 7), B = {4, 6, 8, 10)
kvv77 [185]

Answer:

AuB= {3,4,5,6,7,8,10}

AnB= {4,6}

7 0
3 years ago
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