Answer:
1.
Step-by-step explanation:
Note that 2^4 - 2^3 = 16 - 8 = 8 = 2^3
In a similar way 2^6 - 2^5 = 64 - 32 = 32 = 2^5.
So 2^99 - 2^98 = 2^98 , 2^98 - 2^97 = 2^97 , 2^97 - 2^96 = 2^96 and so on.
Therefore when we come to the last 2 terms we have 2^1 - 2^0 = 2 - 1
= 1 , so the answer is 1.
A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.
B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127
We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y
In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5
x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5
So the cost of each student is $3.5, and the cost of each teacher is $5.
Hope this helps! :)
I think the answer is 8.7332602....I hope I helped!
Answer:
(−3)(+10P)
Step-by-step explanation:
in pic
(Hope this helps can I pls have brainlist (crown) ☺️)
