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liubo4ka [24]
3 years ago
6

Find the coordinates of k

Mathematics
1 answer:
marin [14]3 years ago
4 0
If you plot the coordinates on a piece of graph paper your answer would come out too (1,-8)
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Hayar el patrón 7103425320;_________;7103676328;7103801823
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Don’t understand this question your trying to ask
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Find the height (in millimeters) of a tire sized P285/75R19
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33x12.50R15)

Step-by-step explanation:

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What is the length of a leg of a right triangle if the hypotenuse is 9 inches and the other leg is 8 inches.
adelina 88 [10]

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√17 or 4.12 inches

Step-by-step explanation:

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5 0
3 years ago
The value of 2 in2,783 is what timesthe value of 2 in 7,283
VikaD [51]
The value of 2 in 2,783 is thousand. The value of 2 in 7,283, is hundred. 
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6 0
3 years ago
Read 2 more answers
7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
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