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Mkey [24]
3 years ago
5

What is the side lengths, in inches, of a cube with a volume of 1 1 cubic inch? Branliest

Mathematics
2 answers:
baherus [9]3 years ago
6 0

Answer: A cubic inch is a measure of volume that is equal to a cube with width, length and height are all 1 inch. To calculate the cubic inches in a easy way

Step-by-step explanation:

Mnenie [13.5K]3 years ago
5 0

Answer:

34

Step-by-step explanation:

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Daniel, Jim and David share £80 in the ratio 3:6:7 respectively. David gets the biggest share,
shutvik [7]

Answer:

Got my points deducted by a loser name PoeticAesthetics

Step-by-step explanation:

6 0
3 years ago
PLEASE ANSWER ASAP! YOUR ANSWER MUST INCLUDE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER! THANKS!!!
ZanzabumX [31]
Hello,

Sandy is right .

Other method:
V=168=(10+4)*3*4

3 0
3 years ago
Based on the graph which of the following statements are true
Gre4nikov [31]

you can't really see the question it's too blurry

4 0
3 years ago
Read 2 more answers
Which cube is a unit cube?
liq [111]

Answer:

The answer is (C)

Step-by-step explanation:

because unit cube, more formally a cube of side 1, is a cube whose sides are 1 unit long .The volume of a 3-dimensional unit cube is 1 cubic unit, and its total surface area is 6 square units.

7 0
3 years ago
Read 2 more answers
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
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