How would you expand log412 so that it can be evaluated, given log43 ≈ 0.792?
2 answers:
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Answer:
Step-by-step explanation:
The graph in the attachment is a quadratic function whose vertex is in the fourth quadrant.
The coordinates of a point in the fourth quadrant is of the form
Considering the options, the vertex must have coordinates and
.
The quadratic function in vertex form is written as;
Therefore the equation of the quadratic function is;
The correct answer is option D
Step-by-step explanation:
You can put the value of x into the equation to solve for y. Hopes this works.
