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gulaghasi [49]
3 years ago
11

Suppose a publishing company estimates that its monthly cost is C(x) = 600{x^2} + 300xC(x)=600x 2 +300x and its monthly revenue

is R(x) = - 0.4{x^3} + 700{x^2} - 600x + 500R(x)=−0.4x 3 +700x 2 −600x+500, where x is in thousands of books sold. The profit is the difference between the revenue and the cost.
What is the profit function, P(x)?​

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

the answer is A,

P(x) = -0.4x³+100x²-900x+500

Step-by-step explanation:

monthly cost:

c(x) = 600x {}^{2}  + 300x

monthly revenue:

r(x) =  - 0.4 {}^{3}  + 700x {}^{2}  - 600x + 500

profit function:

p(x) = r(x) - c(x)

p(x) = ( - 0.4x {}^{3}  + 700 {x}^{2} - 600x + 500) - (600x {}^{2}   + 300x)

i) remove the first bracket

p(x) =  - 0.4x {}^{3}  + 700x {}^{2} - 600x + 500 - (600 {x}^{2}   + 300x)

ii) there is a negative sign, '-' in front of the second bracket. so, change the sign of each term of the expression inside the bracket

p(x) =  - 0.4x {}^{3}  + 700 {x}^{2}  - 600x + 500 - 600x {}^{2}  - 300x

iii) collect like terms

p(x) =  - 0.4x {}^{3}  + 700 {x}^{2}  - 600 {x}^{2}  - 600x - 300x + 500

iv) simply the like terms

p(x) =  - 0. 4{x}^{3}  + 100 {x}^{2} - 900x + 500

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