Exact Form:
9
-
16
Decimal Form:
0.5625
That should be it ! :)
we know that
the standard form of the equation of the circle is

where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have

<u>Convert to standard form</u>
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Complete the square twice. Remember to balance the equation by adding the same constants to each side.


Rewrite as perfect squares


the center of the circle is 
the radius of the circle is 
therefore
<u>the answer is</u>
the radius of the circle is 
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Answer:
Step-by-step explanation:
Strictly speaking, 15% isn't precisely the same as 0.15; 0.15 is the decimal fraction used to calculate 15% of some quantity.
15% of 52 is indeed 7.8. $7.80 is the discount that is to be SUBTRACTED from the regular price ($52). Adding $7.80 to $52 is incorrect.
Also, 52 + 7.8 - 59.8 is incorrect: it's not an equation (but should be one), and we should be subtracting $7.80 from $52.
Answer:
The total amount of sugar used=2/3 of a cup
Step-by-step explanation:
The expression for the total amount of sugar used for the cake is;
T=S+O
where;
T=total amount of sugar
S=amount initially added
O=amount sprinkled over the top
This expression can also be written as;
Total amount of sugar=amount initially added+amount sprinkled over the top
In our case;
S=3/6 cup
O=1/6
replacing;
T=(3/6)+(1/6)=4/6 in its lowest form=2/3
The total amount of sugar used=2/3 of a cup