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3 years ago

8

How to do this question plzzz

1 answer:

kiruha [24]3 years ago

6 0

Hi king,

Let's split it into two prisms.

1st prisim volume:

$V_{1}=5cm*10cm*3cm\\V_{1} =150cm^{3}$

2nd prisim volume:

$V_{2}=5cm*10cm*(9cm-5cm)\\V_{2}=5cm*10cm*4cm\\V_{2} =200cm^{3}$

The prism in the picture:

$V_{final}=150cm^{3} +200cm^{3} \\V_{final}=350cm^{3}$

Have a good day.

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elena55 [62]

C is the correct answer

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3 years ago

Read 2 more answers

Pre-Calculus - Systems of Equations with 3 Variables please show work/steps

inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0

3 years ago

Orlov [11]

Answer:

x=100

Step-by-step explanation:

2x + 100 = 300

-100 -100

---------------------

2x = 200

---- -----

2 2

x=100

7 0

3 years ago

Last Sunday 1.575 people visited the amusement park % of the visitors were adults , 16% were teenagers and 28 were children ages

jasenka [17]

Answer:

882 , 252 , 441

Step-by-step explanation:

There are some mistakes in question and the corrected one is written below:

Q. Last Sunday 1,575 people visited the amusement park. 56% of the visitors were adults, 16% were teenagers, and 28% were children ages 12 and under. Find the number of adults, teenagers, and children that visited the park.

Given:

Total number of people visited amusement park = 1,575

Percent of adult people = 56%

Percent of teenagers = 16%

Percent of children = 28%

Now, we have to find number of adults, teenagers, and children that visited the park last Sunday.

Solution:

Number of adults = $56\%\ of \ 1575=\frac{56}{100}\times1575= \frac{88200}{100} =882\ adults$

Number of teenagers = $16\%\ of\ 1575=\frac{16}{100} \times1575=\frac{25200}{100} =252\ teenagers$

Number of children = $28\%\ of\ 1575=\frac{28}{100} \times1575=\frac{44100}{100} =441\ children$

Therefore, the number of adults are 882 , teenagers are 252 , and children are 441 that visited the park last Sunday.

6 0

3 years ago

Help please how can I get this

myrzilka [38]

I tried to do my best to solve and show work. If you need an explanation just leave a comment :)

8 0

3 years ago