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netineya [11]
3 years ago
15

Find the x- and y-intercepts of the graph of each equation. (set x & y equal to 0; two different

Mathematics
1 answer:
bogdanovich [222]3 years ago
5 0
X= 2 y=4 these are the intercepts
You might be interested in
Someone please help me on these 2 problems!
Veronika [31]

1) function  2) not a function

the first one is a function because its y values are the same number (3), which means it is a horizontal line and horizontal lines are functions.  

the second one is not a function because the coordinates cannot have different inputs but different outputs. each input must have only one output.

the coordinates for the second one are:

(2,5); (1,1); (1,2); (3,2)

and <u>a function cannot have two same x-coordinates</u>. it must pass the vertical line test which is a way to tell if something is a function or not. since the second graph does not pass the vertical line test, it is not a function

hope this helps :)

5 0
3 years ago
Can somebody please help...I don’t understand it would mean a lot ❤️
ohaa [14]

Answer:

y=0.5x+8

Step-by-step explanation:

Use the formula for the equation of a line y=mx+c where m is the slope and c is a number.

To find the slope, take two points (x₁,y₁) (x₂,y₂) and put them into the slope equation m=(y₂-y₁)/(x₂-x₁):

We can take two points from the graph: (2,9) (4,10)

m=(y₂-y₁)/(x₂-x₁)

m=(10-9)/(4-2)

m=1/2 or 0.5

Now sub this value in for m and our formula looks like this:

y=0.5x+c

To find the value of c, sub in one of the points, eg. (4,10)

y=0.5x+c

10=0.5(4)+c

10=2+c

c=8

So now that we now m and c, our equation is complete :D

y=0.5x+8

4 0
2 years ago
Read 2 more answers
What is the root?<br> <img src="https://tex.z-dn.net/?f=3-%20%5Csqrt%7Bx%7D%20%3D0%20" id="TexFormula1" title="3- \sqrt{x} =0 "
irga5000 [103]
To solve for x, add 3 to both sides, multiply both sides by -1, then take the square both sides.
3- \sqrt{x} =0\\- \sqrt{x} =-3 \\  \sqrt{x} =3 \\ x=3^2=9

4 0
2 years ago
Given the the table of values below which of the following ordered pairs are found on the graph of the inverse function?
Alja [10]

Answer:

C

Step-by-step explanation:

From the table we see that

f(-2)=12\\ \\f(-1)=10\\ \\f(0)=8\\ \\f(1)=6\\ \\f(2)=4

Thus, the inverse function has the rule

f^{-1}(12)=-2\\ \\f^{-1}(10)=-1\\ \\f^{-1}(8)=0\\ \\f^{-1}(6)=1\\ \\f^{-1}(4)=2

This gives us that ordered pairs

(12,-2),\ (10,-1),\ (8,0),\ (6,1),\ (4,2)

are on the graph of the inverse function

4 0
3 years ago
Read 2 more answers
Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10
LenaWriter [7]

Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

\frac{2}{2} y = \frac{3}{2} x +  \frac{10}{2}

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8

y  = \frac{3}{2} x  - 8

8 0
2 years ago
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