Answer:
A strictly dominant action produces: a higher payoff than any other action the player can use for every possible action of the other players.
Explanation:
A strictly dominant action does not play fair. Here, there is no equality because strict dominance requires all payoffs to be strictly greater.
A strictly dominant strategy is that strategy that always provides greater utility to a the player, no matter what the other player's strategy is.
A rational player will avoid a strictly dominated counterpart because if his opponent uses strictly dominated action he will be come out worse off regardless of which moves other players make.
Answer:
(B) Advice the production and purchasing department to produce or order smaller quantities of products.
Explanation:
According to my research on basic economics and business owning I can say that the best thing for Georgia to do in this situation in order to help her company become more value driven is to Advice the production and purchasing department to produce or order smaller quantities of products. This is because since product is not selling fast enough they should sell what they already have before producing more, otherwise they will be wasting money on products which will eventually cause them to be overflowing stock. Thus losing money.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
The answer is (A)
<em>WAS</em><em> </em><em>THIS</em><em> </em><em>ANSWER</em><em> </em><em>HELPFUL</em><em>?</em><em> </em>
<em>MARK</em><em> </em><em>ME</em><em> </em><em>AS</em><em> </em><em>A</em><em> </em><em>BRAINLIEST</em>
Answer:

Explanation:
Let D be the event that the lost card is a diamond
and D' be the event that the lost card is a non diamond
Therefore,
P(D) =
= 0.25
P(D') =
= 0.75
Now,
Event that the cards picked up are both diamonds = A
Thus,
P( A | D) =
[ As One Diamond Card is lost ]
And,
P(A | D') =
[ As One Non-Diamond card is lost ]
Therefore,
P(A) = P(D) × P(A | D) + P(D') × P( A | D')
= 0.25 ×
+ 0.75 × 
= 