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Pepsi [2]
3 years ago
15

The data set shows the number of hours per week that each student in a class spends studying at home. What is the shape of the d

istribution for this data set?
1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 6, 6, 7



symmetrical



uniform



skewed to the left



skewed to the right
Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

The answer is symmetrical

Step-by-step explanation:

            x

        x  x  x

    x  x  x  x  x

x   x  x  x  x  x  x

___________________________

1   2  3  4  5  6 7

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B<br> [2 0]<br> -2 5<br> What is the determinant of B?<br> Your answer
Marianna [84]

Answer:

10

Step-by-step explanation:

Determinant = ad - bc

\det\begin{pmatrix} 2 & 0 \\-2 & 5\end{pmatrix} =\begin{vmatrix} 2 & 0 \\-2 & 5\end{vmatrix} = 2\times5 + 0\times2 = 10

8 0
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There are 26 students in Jenna's class. Jenna brought in 16 cupcakes. Which equation can be used to find the number of cupcakes
Olin [163]

Answer:

Step-by-step explanation:

16+n=26

26-16=n

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What is the slope and y intercept of y=-x+3
sattari [20]
Y intercept when x =0

<span> y=-x+3
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Tehara has read 115 pages of a 305 page book she reads 10 pages each day how many days will it take to finish
scZoUnD [109]

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305-115=190

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7 0
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Jared has 12 more comic books than Zoe. If they have 28 comic books
ZanzabumX [31]

Answer:

20 comic books

Step-by-step explanation:

Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.

Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

x+x+12=28\\2x+12=28

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

2x=28-12\\2x=16\\x=8

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

x+12=\\8+12=\\20\\

Therefore, Jared has 20 comic books.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

4 0
3 years ago
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